Moment of Inertia: Car vs Sphere

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Homework Help Overview

The discussion revolves around the moment of inertia of a car compared to a sphere, focusing on the dynamics of rolling motion and energy considerations. Participants explore the implications of mass distribution and geometry on the motion of both objects.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to derive equations for the kinetic energy of a car and a sphere, questioning the influence of the car's mass and wheel size on their respective motions. Some participants raise concerns about the assumptions made regarding the mass of the car and its effect on the overall dynamics.

Discussion Status

Participants are actively questioning the role of the car's mass in the context of its wheels and energy distribution. There is a recognition that the mass of the car may significantly influence the outcome, and some guidance has been offered regarding the relevance of the car's body compared to its wheels.

Contextual Notes

Participants note the absence of specific mass values for the objects involved, which complicates the analysis. There is also a discussion about the assumption that the wheels can be considered negligible in terms of mass relative to the car body.

Heyxyz
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Homework Statement
A toy car and a solid metal sphere are rolled down an incline, why does the car reach the bottom first?
Relevant Equations
KE (total) = KE + KE (rotational) = 1/2mv^2 + 1/2Iw^2

Sphere: I = 2/5mr^2

v = wr

w = omega
Hello,

I tried to put it in an equation, but it didn't really work out. In this situation, the car was about the size of a model, and, while not exact, the radius of each wheel couldn't have been more than like a centimeter. Conversely, the ball was like twice the size of the car and had a diameter of 10 - 15 cm.

Ball:

=1/2mv^2 + 1/2I(V/R)^2, I = 2/5mr^2

= 1/2mv^2 + (1/2)(2/5)(m)(r^2)(v^2/r^2)

=7/10mv^2

Car:

Since wheels are practically cylinders, I figured I = 1/2mr^2. There are four wheels, so 4 * 1/2mr^2 = 2mr^2

=1/2mv^2 + 1/2I(V/R)^2, I = 2mr^2

= 1/2mv^2 + 2m(r^2)(v^2/r^2)

=1/mv^2 + mv^2

= 3/2mv^2I don't understand where I'm going. If I follow my above equations, it would appear that the ball reaches the bottom sooner due to the smaller coefficient, but I know that isn't true. Maybe the smaller radius of each wheel has something to do with it?

Thank you.
 
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Heyxyz said:
Since wheels are practically cylinders, I figured I = 1/2mr^2
I doubt the car body is massless. I would take it as being far more massive than the wheels.
 
That's true. Does the car's mass make a difference? I know mass is there, but I just figure it could be ignored (we weren't given masses). I might sound like a fool, but I don't even know how an external mass such as the car would affect the wheels of their velocity.
 
Heyxyz said:
That's true. Does the car's mass make a difference? I know mass is there, but I just figure it could be ignored (we weren't given masses). I might sound like a fool, but I don't even know how an external mass such as the car would affect the wheels of their velocity.
The weight of the car is the primary driving force, much more important than the weight of the wheels. And the mass of the car does not rotate, so all its KE goes into linear motion.
Consider the wheels to be so light in relation to the car that they are irrelevant.
 
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Okay. In other words, the wheels essentially exist so we can ignore friction, and my car's energy should be based on the body of the car rather than the wheels. That actually makes a lot of sense. Thank you.
 
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Heyxyz said:
Okay. In other words, the wheels essentially exist so we can ignore friction, and my car's energy should be based on the body of the car rather than the wheels. That actually makes a lot of sense. Thank you.
Correct.
 

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