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lolzwhut?

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## Homework Statement

A bead slides without friction around a loop-

the-loop. The bead is released from a height

of 26.7 m from the bottom of the loop-the-

loop which has a radius 9 m.

The acceleration of gravity is 9.8 m/s2 .

Diagram:

http://img31.imageshack.us/img31/2377/19550530.png

What is its speed at point A?

Answer in units of m/s.

a of grav = 9.8 m/^2

released from: 26.7 m

loop radius 9 m

## Homework Equations

PE = mgh

Ke = .5mv^2

## The Attempt at a Solution

Ok so this is what I did. I set the PE and KE equations equal to each other so mass can cancel out because its not given.

MGH = .5mv2 >>>> which turns out to be >>> V=sqrt(2*g*h)

To get height i did 26.7-9= 17.7

Then I plugged it into the equation:

v = sqrt(2 * 9.81 * 17.7)

= 18.64 m/s

I submitted the answer and it was wrong still!

omg, someone please explain what am i doing wrong! physics test soon :(

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