Conservation of Momentum in a explosion

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SUMMARY

The discussion centers on the conservation of momentum during the explosion of a firecracker, which initially is at rest. The first fragment has a mass of 14g and moves at 48m/s in the positive x direction. The second fragment, calculated to have a mass of 41g (0.041 kg), moves in the negative x direction at 32m/s. The principle of momentum conservation dictates that the total momentum before and after the explosion remains zero, confirming the direction of the second fragment's motion.

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  • Understanding of momentum (p = mv)
  • Basic knowledge of vector quantities
  • Familiarity with mass and velocity units (grams and meters per second)
  • Concept of conservation laws in physics
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  • Learn about vector addition and subtraction in physics
  • Explore real-world applications of momentum conservation, such as collisions
  • Investigate the effects of mass and velocity changes on momentum
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Students studying physics, particularly those focusing on mechanics and conservation laws, as well as educators looking for practical examples of momentum conservation in explosive events.

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Homework Statement


A firecracker, initially at rest, explodes into two fragments. The first, of mass 14g, moves in the positive x direction at 48m/s. The second moves at 32m/s. Find the mass and direction of its motion.


Homework Equations


p=mv


The Attempt at a Solution



So I know momentum is conserved in this situation. I set m1v1 equal to m2v2 and found the mass of the second fragment to be .041 kg or 41 grams. I think this goes in the negative x direction because the initial momentum is zero and so the sum of all momentums would have to be zero, but I am not sure.
 
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mvl46566 said:

Homework Statement


A firecracker, initially at rest, explodes into two fragments. The first, of mass 14g, moves in the positive x direction at 48m/s. The second moves at 32m/s. Find the mass and direction of its motion.


Homework Equations


p=mv


The Attempt at a Solution



So I know momentum is conserved in this situation. I set m1v1 equal to m2v2 and found the mass of the second fragment to be .041 kg or 41 grams. I think this goes in the negative x direction because the initial momentum is zero and so the sum of all momentums would have to be zero, but I am not sure.
Correct. In the conservation of momentum, the momentum after the explosion = momentum before the explosion. What is the momentum before the explosion?

Remember that momentum is a vector, which has magnitude and direction. We can have to vectors of the same magnitude, but opposite direction, so the sum is zero.
 

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