Conservation of Momentum / Kinetic Energy - What am I doing wrong?

In summary, the white snooker ball has a faster initial velocity and therefore travels further before coming to a stop.
  • #1
bacnka
4
0
I have a problem, I'm trying to work out this simple equation and I'm confusing myself.

This is the question: a white snooker ball hits a stationary red ball elastically at speed of 50cm/second, and both move off at different velocitys. if the balls are the same mass(50g) and the final velocity of the white ball is 20 cm/seconds, what is the final speed of the red ball.

If I use the conservation of momentum equation or equal the KE on both sides of the equation I get different answers? Do i assume that the white balls velocity will be positive on the left side of the equation and negative on the right because the question specifies it's moving in 'different velocities'.

Then if I use ½mv² = ½mv² I get a different answer.

Can someone explain what I am doing wrong?

Thanks!
 
Physics news on Phys.org
  • #2
bacnka said:
Do i assume that the white balls velocity will be positive on the left side of the equation and negative on the right because the question specifies it's moving in 'different velocities'.
You needn't assume anything, just solve the consevation of momentum equation and it will return both the speed and direction of the ball. Different velocities simply means that their velocities are different, but not nesscarily in the opposite direction. Note that momentum is a vector quantity and hence will give you a velocity. However, kinetic energy is a scalar, which means it will return it's speed only and therefore will give you no information regarding the ball's direction.

Notice that the question gives both the final and intial velocities of the white ball as positive, which means that it continues in the same direction.

If you post your working, perhaps we could point out where you're going wrong.
 
Last edited:
  • #3
I'm using m1u2+m2u2=m1v1+m2v2

So I substitute in my values and get:

0.05x0.5 + 0.05x0 = 0.05x0.2 +0.05v

0.025 = 0.01 + 0.05v

0.015 = 0.05v

v=0.30 m/s

But if you equate KE, assuming ½mv²=½mv² so v²=v², 50^2 = 20^2 + v^2

v^2 = 2100

v = 45.38.

Why am I confusing myself?
 
  • #4
if you look at http://hyperphysics.phy-astr.gsu.edu/hbase/elacol2.html#c2, you see that the final velocity for the white ball should be zero. that's a problem. if the problem is inelastic, then your okay(because you have solved for conserved momentum), but even for an elastic collision in which the red ball goes 0.2m/s you will still have anomoulous velocities.
 
Last edited:
  • #5
I think this is a two-dimensional problem; the white ball hits the red ball off-center.

The unknowns are the final speed of the red ball and the two angles of the final velocities. With conservation of momentum and kinetic energy you can write three equations (momentum in x-direction, momentum in y-direction, and KE) and solve for the unknowns.
 

1. How do I calculate conservation of momentum/kinetic energy?

To calculate conservation of momentum, you need to first determine the initial and final momentum of the system. Then, use the equation P(initial) = P(final) to solve for the final momentum. To calculate kinetic energy, use the equation KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

2. Can conservation of momentum/kinetic energy be violated?

No, conservation of momentum and kinetic energy are fundamental laws of physics that have been proven through countless experiments. They cannot be violated and hold true in all situations.

3. What are some real-life applications of conservation of momentum/kinetic energy?

Conservation of momentum and kinetic energy have many practical applications in our daily lives. For example, they are used in car accidents to determine the force of impact and the safety of a vehicle. They are also used in sports, such as calculating the trajectory of a soccer ball or the speed of a baseball pitch.

4. How does friction affect conservation of momentum/kinetic energy?

Friction can affect conservation of momentum and kinetic energy by converting some of the energy into heat or sound. This means that in real-life situations, the final momentum and kinetic energy may not be exactly equal to the initial values due to the presence of external forces like friction.

5. What are some common mistakes when applying conservation of momentum/kinetic energy?

One common mistake is forgetting to take into account all the objects involved in a system and their respective masses and velocities. Another mistake is not considering external forces, such as friction, which can affect the final momentum and kinetic energy. It is important to carefully analyze the situation and consider all factors to accurately apply these principles.

Similar threads

Replies
1
Views
572
Replies
10
Views
425
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
19
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
447
  • Introductory Physics Homework Help
2
Replies
55
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
729
  • Introductory Physics Homework Help
Replies
21
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
1K
Back
Top