A 15 g bullet is fired into a 2.55 kg block that is hanging by a 2.0 m long string. The speed of the bullet is 425 m/s.
Calculate the angle when the system reaches its maximum height?
The Attempt at a Solution
(0.015 kg)(425 m/s) = (0.015 kg + 2.55 kg)vf
(.5)(2.565 kg)(2.49 m/s)^2=(2.565)(9.8)h
Now that I have my height, I am not sure what to do. I think it should be a simple trig function at this point, but I cannot get the correct answer which is 32.6 degrees. I've also tried using L-Lcosθ=h, but have not had luck with that.
Thanks in advance.