Ballistic bullet pendulum conservation of momentum problem

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SUMMARY

The discussion focuses on a conservation of momentum problem involving a 15 g bullet fired into a 2.55 kg block suspended by a 2.0 m string. The bullet's initial speed is 425 m/s, resulting in a final velocity of 2.49 m/s for the combined system. The maximum height reached by the block is calculated to be 0.316 m. The correct angle at maximum height is determined to be 32.6 degrees, which can be found using the equation L - Lcosθ = h.

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fifipaws
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Homework Statement


A 15 g bullet is fired into a 2.55 kg block that is hanging by a 2.0 m long string. The speed of the bullet is 425 m/s.

Calculate the angle when the system reaches its maximum height?

Homework Equations


m1v1=(m1+m2)vf

(1/2)mv^2=mgh

The Attempt at a Solution



(0.015 kg)(425 m/s) = (0.015 kg + 2.55 kg)vf
vf=2.49 m/s

(.5)(2.565 kg)(2.49 m/s)^2=(2.565)(9.8)h
h=.316 m

Now that I have my height, I am not sure what to do. I think it should be a simple trig function at this point, but I cannot get the correct answer which is 32.6 degrees. I've also tried using L-Lcosθ=h, but have not had luck with that.

Thanks in advance.
 
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fifipaws said:

Homework Statement


A 15 g bullet is fired into a 2.55 kg block that is hanging by a 2.0 m long string. The speed of the bullet is 425 m/s.

Calculate the angle when the system reaches its maximum height?


Homework Equations


m1v1=(m1+m2)vf

(1/2)mv^2=mgh


The Attempt at a Solution



(0.015 kg)(425 m/s) = (0.015 kg + 2.55 kg)vf
vf=2.49 m/s

(.5)(2.565 kg)(2.49 m/s)^2=(2.565)(9.8)h
h=.316 m

Now that I have my height, I am not sure what to do. I think it should be a simple trig function at this point, but I cannot get the correct answer which is 32.6 degrees. I've also tried using L-Lcosθ=h, but have not had luck with that.

Thanks in advance.

Your work is correct so far, and yes, use L-Lcosθ=h. What is your problem with it?


ehild
 

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