- #1

peaceandlove

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## Homework Statement

A 4.5 kg block slides along a track from one level to a higher level after passing through an intermediate valley. The track is frictionless until the block reaches the higher level. There a frictional force stops the block in a distance d. The block's initial speed is v0 = 5.3 m/s, the height difference is h = 1.0 m, and μk = 0.613. Find d.

## Homework Equations

E-mec 1 (object moving) = K1 + U1

E-mec 2 (object stopped) = K2 + U2 + energy lost to friction

## The Attempt at a Solution

K1 + U1 - energy lost to friction = K2 + U2

I said that K1=(1/2)mv^2 and U1=mgy and the energy lost to friction is (fk)d; however, I don't know how to get the right side of the equation. I tried using the same formulas and I came up with 1.6313, but apparently that is incorrect.