Elastic potential energy - springs

[icelated]

I know this problem has been asked before but i am trying to understand.

Homework Statement

A 2.00-kg block is pushed against a spring with negligible mass and force constant k = 400 N/m, compressing it 0.220 m. When the block is released, it moves along a frictionless, horizontal surface and then up a frictionless incline with slope 37 degrees

(a) What is the speed of the block as it slides along the horizontal surface after having left the spring?

Homework Equations

K1 + U2 = K2 + U2
Vel = 1/2 kx^2

K = 1/2mv^2

The Attempt at a Solution

If i think of K1 and U1 as the spring compressed then K2 + U2 is the box leaving the spring.
If that logic is correct.?

My teacher has taught us to do this:

K1 =
U1 =
K2 =
U2 =

Now, i am confused on how to fill it in. Then, i can use K1 + U2 = K2 + U2.
can you help me fill in and explain why? I think this will help me understand how to do the problem.

In my mind potential energy is converted to kinetic energy? So, saying K1 + U2 is spring compressed
K1 = 0
U1 = 1/2 kx^2
K2 = 1/2 mv^2
U2 = 0

 

[frogjg2003]

You've done it right.
The box isn't moving initially, so the kinetic energy is 0.
The box isn't compressing the spring when it leaves, so the potential energy is 0.