Consider the circuit shown in the figure below, where C1 = 4.00 µF, C2 = 7.00 µF, and ΔV = 18.0 V. Capacitor C1 is first charged by closing switch S1. Switch S1 is then opened, and the charged capacitor is connected to the uncharged capacitor by closing S2.(adsbygoogle = window.adsbygoogle || []).push({});

(a) Calculate the initial charge acquired by

C1.

This I got to be 72μC

(b) Calculate the final charge on each capacitor.

This is where I am stuck...

Q1' = 72μC - Q2'

(72μC) - Q2'

___________ =

(4μF)

Q2'

____________

(7μF)

I know that I am supposed to solve for Q2' at this point but I don't know how.

Can someone please please help me??

Once I find Q2' then I can find Q1 by taking (72μC) - (Q2)...correct??

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# Consider the circuit shown in the figure below, where C1 = 4.00 µF, C2

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