Morbert
Gold Member
- 1,009
- 771
Then let's try to discuss the ideal experiment (so no loopholes) where a two-particle system is prepared in a correlated state such that no matter the aspect chosen, the outcomes will be identical with 100% certainty. Below is my attempt to formalise this without recourse to CH. I use unitary evolution of the entire system, but I don't ascribe meaning to it beyond a tool for computing probabilities.DrChinese said:Yes, that's my intention. The idea is that the outcomes are specific and identical, let's say both a +1 outcome at 19 degrees (I just picked this out of thin air). Or both -1 at 56 degrees (also out of thin air). Variations of that can be tested with the cited Hensen experiment (although they use different angle settings, the expectation values match QM; and CH must too).
So by what standard can Griffiths say "appropriate measurements can reveal quantum properties possessed by the measured system before the measurement took place" and it NOT mean the same thing as Bell or myself? He is apparently drawing some distinction between: a) "hidden variables" (those don't exist); and b) "true" realism (which because it is different than Bell realism, means that Bell inequalities don't apply).
Well, my example does not rely on Bell or CHSH. It is back to EPR-type reasoning (elements of reality). So either the measurement outcome of A is independent of the setting at distant B; or it isn't. Which? Because if they match, the question immediately becomes: how do 2 independently oriented electrons suddenly match spins without violating the very Einsteinian locality that is central to CH? Given they had those "quantum properties" prior to measurement, also according to CH.
We have a two-particle system prepared in a Bell state ##|\phi^+\rangle = \frac{1}{\sqrt{2}}(|\uparrow_\omega\uparrow_\omega\rangle + |\downarrow_\omega\downarrow_\omega\rangle)##, a quantum random number generator (QRNG) that chooses an aspect ##\omega## and distant labs ##A## and ##B## that each measure one of the photons in the ##\omega## basis, with each with outcomes 1 or 0. Quantum mechanics predicts identical outcomes regardless of aspect.
The three components above are prepared in the initial state $$|\Psi_0\rangle = |\Omega\rangle_{QRNG}|\Omega\rangle_{AB}|\phi^+\rangle_{12}$$Evolving to the moment the measurements conclude, we have the state $$|\Psi_1\rangle = \sum_{\omega}\frac{c_\omega}{\sqrt{2}}|\omega\rangle_\mathrm{QRNG}(|11\rangle_{AB12} + |00\rangle_{AB12})$$We want the probability that the outcomes will be correlated, given any aspect. I.e. ##\mathrm{Pr}(11 \lor 00 | \omega)##. Dropping the subscripts where possible:
\begin{eqnarray*}
\mathrm{Pr}(\omega) &=& \mathrm{tr} \left[\Psi_1\right]\otimes\left[\omega\right]\otimes I_{AB12} &=& |c_\omega|^2\\
\mathrm{Pr}(\left[11 \lor 00\right]\land\omega) &=& \mathrm{tr}\left[\Psi_1\right]\otimes\left[\omega\right]\otimes(\left[11\right] + \left[00\right])&=& |c_\omega|^2\\
\mathrm{Pr}(11 \lor 00 | \omega) &=& \frac{\mathrm{Pr}(\left[11 \lor 00\right]\land\omega)}{\mathrm{Pr}(\omega)} &=& 1
\end{eqnarray*}Before discussing how CH would introduce realism to this scenario, maybe it is good to first see if we agree with this simple model of the experiment.
[edit] - Clarified some things
[edit 2] - Simplified Bell state expression and removed potentially misleading coefficients
Last edited: