Consservation of energy problem

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SUMMARY

The conservation of energy problem involves a 50 kg skier starting from a height of 25 m on a frictionless ramp, launching at an angle of 28° with the horizontal. The initial potential energy is calculated using the formula U_i = m * g * H, where g is the acceleration due to gravity. As the skier leaves the ramp, his vertical velocity can be determined using v^2 = 2gH, and at the maximum height of the jump, the vertical velocity becomes zero. The maximum height h above the ramp can then be calculated using energy conservation principles.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Familiarity with potential and kinetic energy equations
  • Knowledge of projectile motion and vertical velocity calculations
  • Basic grasp of trigonometry, specifically angles in projectile motion
NEXT STEPS
  • Calculate the initial potential energy using U_i = m * g * H
  • Determine the vertical velocity at the end of the ramp using v^2 = 2gH
  • Apply the conservation of energy equation to find the maximum height h
  • Explore the effects of different launch angles on maximum height in projectile motion
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of energy principles in action.

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Homework Statement



A 50 kg skier starts from rest at a height of H = 25 m above the end of the ski-jump ramp. As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless.

What is the maximum height h of his jump above the end of the ramp?


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Homework Equations



I was using the conservation of energy equation:[tex]\textit{K_{i}+U_{i}+W = K_{f}+U_{f}}[/tex]
but I am getting stuck. I'm just not sure how to approach this problem. Using the initial kinetic energy as 0 and the initial potential energy as mass*gravity*height and that equals the kinetic energy plus the potential energy due to gravity at the height above the ramp. I don't know what the kinetic energy would be at this point so I cannot solve for the height. Am I looking at this correctly?
 
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When the skier is at H = 25 m, his vertical velocity is given by v^2 = 2gH.
Since ramp is frictionless, the same vertical velocity will be there when he leaves the ramp at an angel 28 degrees. When he is at the highest point his vertical velocity will be zero. Now find h.
 
Thank you for your help!
 

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