Constant acceleration equations (SUVAT)

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SUMMARY

The discussion focuses on solving a physics problem involving constant acceleration equations (SUVAT) related to a stone projected horizontally from a 49m high cliff with an initial speed of 20 m/s. The key conclusion is that to determine the time it takes for the stone to reach the sea, one should only consider the vertical motion, using the equation t = √(2d/g), where d is the height of the cliff and g is the acceleration due to gravity (approximately 9.81 m/s²). The initial horizontal velocity does not affect the time of descent.

PREREQUISITES
  • Understanding of constant acceleration equations (SUVAT)
  • Knowledge of vertical motion and gravitational acceleration
  • Familiarity with basic kinematic equations
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of the equation t = √(2d/g) for free fall
  • Learn about the implications of horizontal and vertical motion in projectile motion
  • Explore the concept of initial velocity in different directions
  • Investigate the effects of air resistance on projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and projectile motion, as well as educators looking for clear examples of applying SUVAT equations in real-world scenarios.

sharbie
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Homework Statement


A stone is projected horizontally from the top of a vertical sea cliff 49m high, with a speed of 20ms^-1. Neglecting air resistance, calculate:
The time that it takes to reach the sea.



Homework Equations


v² =u²+2as
t=v-u/a
t=d/s


The Attempt at a Solution


I'm not sure whether i should be calculating v-final velocity via v² =u²+2as and using that to find t, ie. t=v-u/a
or simply
t=d/s

can anybody enlighten me please? thanks
 
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sorry about the layout by the way, don't know what happened there- first time user :smile: anyway, would much appreciate help please :smile:
 
The only thing you're concerned with (for the problem, as stated) is the time it takes to drop vertically. And, since it's projected horizontally, it doesn't matter what the initial velocity is. Hint: v_0y = 0.

You need to use the constant-acceleration equation that relates initial position, final position, acceleration, time, and initial velocity (0 m/s).EDIT: You don't need (for this problem) to find out the final velocity.
 

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