Constant Acceleration of car over distance

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SUMMARY

The discussion revolves around calculating the time it takes for a car to cover a distance (L) under constant acceleration (a) while starting and ending at rest. Two scenarios are analyzed: one where the car does not reach its maximum velocity (v) and another where it does. For the first scenario, the time (t) is derived using the formula t = sqrt(L/a). In the second scenario, the calculations require additional information about the maximum velocity and the relationship between distance, acceleration, and time.

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  • Understanding of kinematic equations, specifically S = 0.5at²
  • Knowledge of constant acceleration concepts
  • Familiarity with maximum velocity (v) in motion problems
  • Basic algebra for solving equations
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Mglafas
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I'm trying to do the following problem:

A car can accelerate and brake with constant acceleration, both with the magnitude (a). The car has a maximum velocity (v). The car needs to cover the distance (L), starting and ending at rest.

a) How long will it take the car to cover the distance if the maximum velocity (v) is NOT reached?

b) How long will it take the car to cover the distance if the maximum velocity (v) IS reached?



I only become increasingly confused the more I try to understand this question. If the car does not reach its maximum velocity in the first question, then how will it do so in the second when the acceleration and distance is a constant?

If I ignore (v), then i get this:
S=0.5at^2
(L/2)=0.5at^2
t=sqrt(aL)

Can anyone help?
 
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Mglafas said:
If the car does not reach its maximum velocity in the first question, then how will it do so in the second when the acceleration and distance is a constant?

I think what they meant in the questions is (a) solve it IF the car does not reach maximum velocity, (b) solve it IF the car does reach maximum velocity.
so you don't know what are L,a,v, so you don't know which one is true, therefore you must solve both cases, but you can't say (a) is true and (b) is not.
 

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