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mstud
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Homework Statement
You drop a stone down into a well to find the depth of the well. You hear the sound of the splash 3.5 s after you let the stone go.
Homework Equations
[tex]s(displacement)=v_0t \cdot \frac 12 at^2[/tex]
The Attempt at a Solution
I have
[itex]t_{total}=3.5 s[/itex]
Stone: [itex]v_0[/itex]=0, and a=9.81 m/s^2.
Sound: v=340 m/s, a=0.
If the sound had not used a small part of the total time, the answer would have been:
[tex]s(displacement)=v_0t \cdot \frac 12 at^2=0*3.5 s + \frac 12 * 9.81 m/s^2*(3.5s)^2=60 m[/tex]
But the answer key of my book says 55 m. I see why, but I don't know how I can get that answer... Please help, anybody out there!