Constant for different types of lattices

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In summary, the constant ##C## is calculated as the sum of the exchange integral ##J(0)## divided by the difference between ##J(0)## and ##J(\vec{k})## in ##\vec{k}## space. This constant is also known as ##C_{SC}## for a simple cubic lattice and has a value of 1.516. It is surprising that this constant is universal for all simple cubic lattices despite variations in lattice constants and atomic flavor. ##J(0)## favors ferromagnetism, while ##J(\vec{k})## with ##\vec{k} \neq 0## favors antiferromagnetism with a modulation wave vector ##\vec{k
  • #1
LagrangeEuler
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##C=\frac{1}{N}\sum_{\vec{k}} \frac{J(0)}{J(0)-J(\vec{k})} ##
##J(\vec{k})## is exchange integral in ##\vec{k}## space. What is the name of this constant and where I can find more about it?

For simple cubic lattice
##C_{SC}=1.516##
 
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  • #2
Can you provide a bit more context?

Exchange integrals usually depend on details of the band structure, so I am surprised that you can get a universal constant for all simple cubic lattices irrespective of lattice constant, atomic flavor etc.

J(0) would favor ferromagnetism

J(k) with k != 0 would favor antiferromagnetism with a modulation wave vector k.
 
  • #3
See this paper.
 

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  • Watson Original paper.pdf
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  • #4
Or here.
 

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  • Tahir-Kheli I.pdf
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What is the constant for a simple cubic lattice?

The constant for a simple cubic lattice is typically represented by the letter "a" and is equal to the length of one side of the cube.

How does the constant differ for a face-centered cubic lattice compared to a simple cubic lattice?

The constant for a face-centered cubic lattice, also represented by "a", is equal to √2 times the length of one side of the cube. This is because the face-centered cubic lattice has atoms located at the center of each face in addition to the corners, resulting in a larger unit cell.

What is the constant for a body-centered cubic lattice?

The constant for a body-centered cubic lattice, also represented by "a", is equal to √3 times the length of one side of the cube. This is because the body-centered cubic lattice has an additional atom located at the center of the cube, resulting in a larger unit cell.

How does the constant for a hexagonal close-packed lattice compare to the constant for a face-centered cubic lattice?

The constant for a hexagonal close-packed lattice, represented by "a", is equal to √8/3 times the length of one side of the cube. This is because the hexagonal close-packed lattice has an additional atom located at the center of each face, resulting in a larger unit cell compared to the face-centered cubic lattice.

Is the constant the same for all types of lattices?

No, the constant can vary depending on the type of lattice. Different lattice structures have different arrangements of atoms, resulting in different unit cell sizes and therefore different constants.

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