Constant Pressure Calorimetry with Piston

Click For Summary
SUMMARY

The discussion centers on constant pressure calorimetry involving a calorimeter with a sliding piston, specifically examining the combustion of 1.250 octane at an initial temperature of 25 degrees Celsius. The consensus is that the calorimeter's temperature will rise due to the exothermic nature of the reaction. However, the volume of the system is expected to decrease despite the temperature increase, as the moles of gas decrease during combustion. The work done by the system is classified as positive, although this raises questions about the relationship between work and volume changes in the context of the calorimeter.

PREREQUISITES
  • Understanding of constant pressure calorimetry
  • Familiarity with the ideal gas law
  • Knowledge of exothermic reactions and their effects on temperature
  • Basic concepts of thermodynamics related to work and volume
NEXT STEPS
  • Study the principles of constant pressure calorimetry in detail
  • Learn about the ideal gas law and its applications in chemical reactions
  • Investigate the thermodynamic concepts of work and heat transfer
  • Examine the combustion reactions of hydrocarbons, particularly octane
USEFUL FOR

Chemistry students, educators, and professionals involved in thermodynamics and calorimetry, particularly those focusing on combustion reactions and their implications in calorimetric measurements.

twotwntytwo
Messages
2
Reaction score
0
This is a conceptual question...hope you guys can explain the answers that the book gives! Its frustrating me to no end. This is actually a problem in the Enthalpy chapter, calorimetry section of section exercises of the Olmsted and Williams chemistry textbook, 3rd ed.

Any help would be GREATLY appreciated! Is this just a poorly worded question, or do I have the incorrect concept?

Q: Imagine a calorimeter with a sliding piston that makes it able to perform constant pressure calorimetry experiments on a mixture of gasses and liquids

Consider burning 1.250 octane in this calorimeter, which is initially at 25 degrees celsius

Q1: Will the calorimeter temperature rise or fall?
A: Rise

[note: I understand this, since burning octane is an exothermic reaction, leading to the loss of heat from the piston to the calorimeter]

Q2: Use the ideal gas equation to determine whether the volume of the system will increase or decrease. (The temperature after burning rises about 6 degrees celsius)
A: Decrease: The volume will decrease. Although the temp rises slightly, the moles of gas decrease

[note: I don't understand this! Since it is exothermic, doesn't the reaction cause work to be performed on the piston, increasing the volume of the piston?]

Q3: Is the work, negative, positive, or zero?
A: Positive

[note: i agree with this answer. however, it seems to contradict the last answer. also, the question is not specific as to what is experiencing the work, the piston or calorimeter]
 
Physics news on Phys.org
Reaction equation will help, although I feel like second part is a little bit ambiguous.

--
methods
 
Hi Borek-

No equation is provided with the problem, although I think the reaction is combustion and the liquid gas mixture they are referring to is the mixture of octane, water, and co2

2C8H18 +25O2-----16CO2+H20

Thanks for responding! And I agree that the question is vague, the answers given seem to be contradictory :(
 
18H2O, but I suppose it is a just a typo.

Trick is - we don't know what is the final temperature. If it is below 100 deg C, water is liquid - you have started with 25 volumes of gas, you are left with 16 volumes. Does it mean increase or decrease of volume?

--
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
49
Views
3K
  • · Replies 2 ·
Replies
2
Views
11K
  • · Replies 6 ·
Replies
6
Views
618
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K