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Ideal Gas Law Gas in a Piston Problem

  1. Jan 13, 2012 #1
    1. The problem statement, all variables and given/known data
    A gas is in a piston which is at 25 degrees celsius with a volume 4.0L is held in a room at atmospheric pressure. If the temperature is increased to 193 degrees celsius, the piston expands to it's maximum volume. If the pressure in the room is then increased to 4.3 atm, what is the new volume of the piston (temperature remains at 193 degrees celsius)?

    T1 = 25 = 298.15K

    V1 = 4.00L

    P1 = 1.000atm

    P2 = 4.3 atm

    T2 = 466.15K

    V2 = ?


    2. Relevant equations

    P1V1 / T1 = P2V2 / T2

    3. The attempt at a solution

    P1V1 / T1 = P2V2 / T2

    V2 = P1V1T2 / T1P2

    V2 = (1.000atm)(4.0L)(466.15K) / (298.15K)(4.3atm)

    = 1.45L
    = 1.5L

    Just want someone to check my solution
     
  2. jcsd
  3. Jan 14, 2012 #2
    Looks correct.
     
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