Ideal Gas Law Gas in a Piston Problem

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SUMMARY

The discussion centers on solving a gas law problem using the Ideal Gas Law equation, specifically P1V1 / T1 = P2V2 / T2. Given initial conditions of 25 degrees Celsius (298.15K) and a volume of 4.0L at 1.0 atm, the problem calculates the new volume (V2) when the pressure is increased to 4.3 atm at a temperature of 193 degrees Celsius (466.15K). The final calculated volume is approximately 1.5L, confirming the solution's accuracy.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of temperature conversion between Celsius and Kelvin
  • Ability to manipulate algebraic equations
  • Familiarity with pressure units (atm)
NEXT STEPS
  • Study the derivation and applications of the Ideal Gas Law
  • Learn about the relationships between pressure, volume, and temperature in gas behavior
  • Explore real-world applications of gas laws in engineering and physics
  • Investigate the effects of non-ideal conditions on gas behavior
USEFUL FOR

Students in chemistry or physics courses, educators teaching gas laws, and professionals in fields requiring thermodynamic calculations.

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Homework Statement


A gas is in a piston which is at 25 degrees celsius with a volume 4.0L is held in a room at atmospheric pressure. If the temperature is increased to 193 degrees celsius, the piston expands to it's maximum volume. If the pressure in the room is then increased to 4.3 atm, what is the new volume of the piston (temperature remains at 193 degrees celsius)?

T1 = 25 = 298.15K

V1 = 4.00L

P1 = 1.000atm

P2 = 4.3 atm

T2 = 466.15K

V2 = ?


Homework Equations



P1V1 / T1 = P2V2 / T2

The Attempt at a Solution



P1V1 / T1 = P2V2 / T2

V2 = P1V1T2 / T1P2

V2 = (1.000atm)(4.0L)(466.15K) / (298.15K)(4.3atm)

= 1.45L
= 1.5L

Just want someone to check my solution
 
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Looks correct.
 

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