Ideal Gas Law Gas in a Piston Problem

[maceng7]

Homework Statement

A gas is in a piston which is at 25 degrees celsius with a volume 4.0L is held in a room at atmospheric pressure. If the temperature is increased to 193 degrees celsius, the piston expands to it's maximum volume. If the pressure in the room is then increased to 4.3 atm, what is the new volume of the piston (temperature remains at 193 degrees celsius)?

T1 = 25 = 298.15K

V1 = 4.00L

P1 = 1.000atm

P2 = 4.3 atm

T2 = 466.15K

V2 = ?

Homework Equations

P1V1 / T1 = P2V2 / T2

The Attempt at a Solution

P1V1 / T1 = P2V2 / T2

V2 = P1V1T2 / T1P2

V2 = (1.000atm)(4.0L)(466.15K) / (298.15K)(4.3atm)

= 1.45L
= 1.5L

Just want someone to check my solution

 

[LawrenceC]

Looks correct.