Constant that makes g(x) continous over (-inf,inf)

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Homework Help Overview

The problem involves finding a constant \( c \) that ensures the function \( g(x) \) is continuous across all real numbers. The function is defined piecewise, with a quadratic expression for \( x < 4 \) and a linear expression for \( x \geq 4 \).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the continuity of the function at the point \( x = 4 \) and the need to equate limits from both sides. There is mention of solving an equation involving \( c \) and considerations about the quadratic formula.

Discussion Status

Some participants provide guidance on checking the equations and suggest that the original poster may have made an error in their setup. There is a mix of opinions on the best approach to take, with some advocating for careful consideration of the equations before applying methods like the quadratic formula.

Contextual Notes

Participants note the importance of ensuring the correct formulation of the equations before proceeding with solving for \( c \). There is an acknowledgment of the potential for sign errors in the equations presented.

JeffNYC
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Homework Statement



Find the C (constant) that makes the function g(x) continuous over all real numbers.


Homework Equations



g(x) = x^2 - c^2 | if x < 4

= cx + 20 | if x >= 4

The Attempt at a Solution



Since the function is composed of a quadratic and a polynomial they are continuous over all real numbers. Thus, the only possible point of discontinuity lies at x = 4.

lim g(x) as x -> 4 = 4c + 20

I need to make the limit of g(x) as x -> 4 from the left equal to the above limit.

So logically I need to solve for c

c4 + 20 = 4^2 + c^2

Assuming I've thought this through correctly up until this point...I guess I just can't solve the equation. Do I need to use the quadratic formula?

Thanks Guys,

Jeff
 
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Quadratic formula sounds like a good place to start.
 
Actually, I believe that thinking rather than the quadratic formula is a good place to start! Go back and check your equations. You should not have 4c+ 20= 42+ c! You've dropped a sign.
 
Well, yeah, thinking is always good, but he *thought* he should try the quadratic formula and I think he's right in the sense that it will give him the correct answer.
 
It would be better to think the correct equation first!

My real point was that if he had the right equation, it would be trivial to factor.
 

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