Constraints and Static Determinacy

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A structure can be completely constrained and still be statically indeterminate, while a partially constrained structure cannot be statically determinate. Completely constrained structures are stable, whereas partially constrained and improperly constrained structures are unstable, with the latter having the wrong configuration of constraints. An example of a statically indeterminate structure is a bar fixed at both ends with a force applied in the middle, which cannot be solved using static equations. Conversely, a beam on two rollers with a downward force is statically determinate but underconstrained, as it can move laterally. Understanding these distinctions is crucial for analyzing structural stability and determinacy.
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Hello,

Is it possible for a structure to be completely constrained and statically indeterminate, or partially constrained and statically determinate? Or does one come with the other automatically?

I am having difficulties determining if a structure is partially constrained or completely constrained, or improperly constrained.
 
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Woopydalan said:
Is it possible for a structure to be completely constrained and statically indeterminate?
Yes.

Woopydalan said:
Is it possible for a structure to be partially constrained and statically determinate?
No.

Woopydalan said:
Or does one come with the other automatically?
No.

Woopydalan said:
I am having difficulties determining if a structure is completely constrained, partially constrained, or improperly constrained.
A completely constrained structure is static (stable).

Partially constrained and improperly constrained structures are quite similar. They are both nonstatic (unstable). The only subtle difference between the two is, a partially constrained structure has an insufficient number of constraints, whereas an improperly constrained structure has a sufficient number of constraints, but the constraints are configured wrong, such that the structure is still nonstatic (unstable, moves).
 
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Yes. Consider a bar fixed rigidly at both ends to opposing walls and a force applied in the middle of the bar. The bar is fully constrained, but the reaction forces can't be solved with just the equations of statics, making it statically indeterminate.

You could say that the beam in the above example is "overconstrained", and by that I mean that the bar could still be fully constrained without fixing both ends. A cantilever beam is fully constrained in translation and rotation as well, and that problem is statically determinate. I know that's not the exact meaning of "overconstrained", but I'm just trying to illustrate that point.

You also have cases where things are statically determinate but not fully constrained. Consider a beam on 2 rollers with a vertical force being applied downward. The system is statically determinate, meaning you can solve for the reaction forces at the rollers with just the equations of statics, but the system is underconstrained because any lateral force on the beam will cause it to move.
 
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