Construct a 2x2 nilpotent matrix

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To construct a 2x2 nilpotent matrix, the key equations derived from its properties include tr(M) = 0 and det(M) = 0, which lead to the equations a + d = 0 and ad = bc. The discussion highlights that while the first equation is already established, the second is implicitly represented by the kernel conditions. Participants debate the necessity of additional equations, with one asserting that the existing equations are sufficient for determining the matrix. Ultimately, the conclusion is that the nilpotent nature of the matrix can be encapsulated by the two equations related to its trace and determinant.
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Homework Statement


Costruct a:

Schermata 2018-04-17 14:21:36.png

The Attempt at a Solution



I found 3 equations but i miss another one :(

<br /> M=\begin{bmatrix}<br /> a &amp; b\\<br /> c &amp; d<br /> \end{bmatrix}

(1) a+d = 0 from the definition of nilpotent matrix
(2) a+3b = 0 from kernel
(3) c +3d= 0 from kernel
 

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Aleoa said:

Homework Statement


Costruct a:

View attachment 224200

The Attempt at a Solution



I found 3 equations but i miss another one :(

<br /> M=\begin{bmatrix}<br /> a &amp; b\\<br /> c &amp; d<br /> \end{bmatrix}

(1) a+d = 0 from the definition of nilpotent matrix
(2) a+3b = 0 from kernel
(3) c +3d= 0 from kernel
You're missing an equation that results from ##M^2 = 0##.
 
Mark44 said:
You're missing an equation that results from ##M^2 = 0##.

I know that the equations of the nilpotent matrix are:

a+d=0
and
ad=bc.

However, the first it's already present, the second it's implicitely represented by the 2 kernel equations
 
Aleoa said:
I know that the equations of the nilpotent matrix are:

a+d=0
and
ad=bc.
Yes, you already said that in post #1, but you're not using the fact that the matrix is nilpotent.
Aleoa said:
However, the first it's already present, the second it's implicitely represented by the 2 kernel equations
Using the fact that tr(M) = 0, you have a + d = 0.
So M could be written as ##M = \begin{bmatrix} a & b \\ c & -a \end{bmatrix}##. Then ##M^2## = what?
 
Mark44 said:
Yes, you already said that in post #1, but you're not using the fact that the matrix is nilpotent.

Using the fact that tr(M) = 0, you have a + d = 0.
So M could be written as ##M = \begin{bmatrix} a & b \\ c & -a \end{bmatrix}##. Then ##M^2## = what?

The fact that the matrix is nilpotent is totally determined by the 2 equations:
tr = 0
det = 0

Maybe I am wrong, but the book I am studying argues this.

So, i miss another equation...
 
Last edited:
Aleoa said:
The fact that the matrix is nilpotent is totally determined by the 2 equations:
tr = 0
det = 0

Maybe I am wrong, but the book I am studying argues this.

So, i miss another equation...

You have enough equations now.
 
PeroK said:
You have enough equations now.

Unfortunately no. The tr=0 equation was already present and the det is implied by the 2 kernel equations
 
Aleoa said:
Unfortunately no. The tr equation was already present and the other it's implied by the 2 kernel equations

How many equations do you need for two variables?
 
The question does not imply that there is only one possible answer.
 

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