Constructing a Continuous Function with 2 Different Range Values

  • Thread starter Thread starter muzihc
  • Start date Start date
  • Tags Tags
    Continuity
Click For Summary
SUMMARY

The discussion centers on the challenge of constructing a continuous function f:D-->R with a range consisting of only two distinct values. Participants debate the feasibility of such a function, referencing the Intermediate Value Theorem, which asserts that continuous functions cannot have jumps. Despite differing opinions, the consensus leans towards the impossibility of achieving this under standard topological definitions. The professor's assertion that it is possible suggests a deeper exploration of continuity definitions is necessary.

PREREQUISITES
  • Understanding of continuous functions in topology
  • Familiarity with the Intermediate Value Theorem
  • Knowledge of discrete sets in mathematical analysis
  • Basic concepts of function mapping from D to R
NEXT STEPS
  • Study the definitions of continuity in various topological spaces
  • Explore examples of continuous functions and their ranges
  • Investigate the implications of the Intermediate Value Theorem
  • Examine discrete topology and its properties regarding continuity
USEFUL FOR

Mathematics students, educators, and anyone interested in the properties of continuous functions and their applications in topology.

muzihc
Messages
15
Reaction score
0

Homework Statement


Provide an example of f:D-->R which is continuous but whose range has two different numbers only.


Homework Equations





The Attempt at a Solution


For the range to have only two different values, it's seems impossible to construct a continuous function without jumps. In fact, it seems like the intermediate value theorem could prove this.

I've asked my professor if this is possible, he says it is, and that studying the definitions of continuous closely will reveal it.

Then I've asked a few friends, who are very good at math, and they say it isn't. I also asked Dr. Math, and got a response from Dr. Tom, who says it isn't.
 
Physics news on Phys.org
In the usual topology, any function from a discrete set is continuous.
 
snipez90 said:
In the usual topology, any function from a discrete set is continuous.

Thanks

I feel like a moron.
 

Similar threads

Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K