Constructing a Feynman loop integral

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ryanwilk
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Homework Statement



I need to construct the Feynman loop integral for the following diagram:

Feynman diagram of a one-loop self-energy: external left-handed neutrino nu_L enters, emits a dashed scalar line labelled phi and an internal solid line labelled N with a Majorana mass insertion marked by a cross, then exits as nu_L.
(*)

where [itex]\nu[/itex]L is the left-handed neutrino, [itex]\phi[/itex] is a scalar particle and N is a heavy neutrino with a Majorana mass.

Homework Equations



N/A

The Attempt at a Solution



I'm trying to determine it by comparing it to the self-energy of the electron:

Feynman diagram of a one-loop self-energy: a horizontal fermion line with an arrow, with a wavy internal loop (scalar propagator) drawn as a wavy line above it.


which gives

Feynman loop integral for a self-energy: ie^2 Sigma(p) = integral of d^4k/(2pi)^4 times (-ie gamma_mu) times (-i g^{mu nu})/(k^2 + i epsilon) times i/(pslash - kslash - m + i epsilon) times (-ie gamma_nu).
.

1) Since there's a scalar propagator ([itex]\phi[/itex]) in (*), do I need to use these Feynman rules?:

Two Feynman rule diagrams: a dotted scalar line phi with a dot at each end and momentum q arrow gives +i/(q^2 - m^2 + i0); a vertex with a dotted line meeting two fermion lines beta and alpha gives -ig delta_{beta alpha}.


where m = m[itex]\phi[/itex] in this case. (Taken from http://bolvan.ph.utexas.edu/~vadim/Classes/2011f/QED.pdf).

2) How do I deal with the fact that the neutrinos are left-handed? Do I just add factors of (1-γ5)/2 in the (-igδβα) terms?

3) For Dirac particles, the propagator is:

Propagator fraction: numerator i over denominator p-hat minus k-hat minus m plus i epsilon, written as plain fermion propagator form.


But how does this change if the particle (in this case, N) is Majorana?Any help would be appreciated.

Thanks!
 
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Have you been given a Lagrangian? It would be much better to work out the Feynman rules from that rather than try to guess at bits and pieces that might not quite fit what you want.
 
The Lagrangian is:

L = L[itex]\varphi[/itex] + LSM where

L[itex]\varphi[/itex] = [itex]\frac{1}{2}[/itex]∂μ[itex]\phi[/itex]+∂μ[itex]\phi[/itex] + [itex]\frac{m^2}{2}[/itex][itex]\phi[/itex]+[itex]\phi[/itex] + [itex]\frac{λ}{4}[/itex]([itex]\phi[/itex]+[itex]\phi[/itex])2 + g[itex]\phi[/itex][itex]\overline{N_R}[/itex][itex]\nu[/itex]L + [itex]\frac{m_N}{2}[/itex]NRTCNR + h.c.

(g = coupling constant, N = Majorana neutrino, [itex]\phi[/itex] = Neutral scalar, [itex]\nu[/itex]L = LH neutrino),

However, I was told just to construct it from Feynman rules. Also, I have no idea how to go from this complicated Lagrangian to the integral =/.
 
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