Constructing a Proportional Growth Equation for Bacterial Population

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The discussion centers on constructing a proportional growth equation for a bacterial population that starts with 820 bacteria and grows to 2460 bacteria in 3 hours. The correct differential equation is expressed as \(\frac{dy}{dt}=ky\), where \(k\) is the constant of proportionality. The initial conditions allow for the calculation of \(k\) through integration. The initial attempt at solving the equation was incorrect due to the omission of the proportionality constant.

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glid02
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Here's the question:
A bacteria culture starts with 820 bacteria and grows at a rate proportional to its size. After 3 hours there will be 2460 bacteria.

(a) Express the population after t hours as a function of t.

I tried y=y'+820, so -y'+y=820
p(t)=1
mu(t)=e^t

I carried this out (multiplying both sides by mu(t) and finding the integral of both sides) and it's not right.

I really don't even know where to start - is finding mu(t) even the right approach?

Thanks a lot.
 
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Your first equation is incorrect.
A bacteria culture starts with 820 bacteria and grows at a rate proportional to its size.

The correct equation for this system would be: \frac{dy}{dt}=ky, where k is the constant of proportionality; your equation omitted this!

Try integrating this. The numbers are there as the boundary conditions of the system, to enable you to calculate the constants.
 
Yep, that was it. Thanks.
 

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