Constructing Matrix E and F for RowA and NulA Basis | Homework Explanation

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SUMMARY

The discussion focuses on constructing matrices E and F from the basis vectors of rowA and nulA, respectively, and computing their product EF. The basis for nulA is given as { [3 2 1 0], [1 3 0 1] } and for rowA as { [1 0 2 4], [0 1 3 2] }. The computed product EF results in the zero matrix, which is explained by the property that the null space consists of vectors that are mapped to the zero vector by the matrix, confirming the relationship between the row space and null space.

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Homework Statement


Construct a matrix E such that its rows are the basis vectors for rowA and a matrix F such that its columns are the basis vectors for nulA. Compute EF. Explain your results.


Homework Equations


Basis for NulA was { [3 2 1 0], [1 3 0 1] } (except vertical)
Basis for RowA was { [1 0 2 4], [0 1 3 2] } (except vertical)


The Attempt at a Solution


I computed EF and I got the zero matrix, but I'm not sure exactly why this is the case. Can someone provide some insight on this? Thanks.
 
Last edited:
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What is nullspace?
 


NoMoreExams said:
What is nullspace?
Edit: DOH, nevermind, I get it now. The null space is the vectors that get mapped to the zero vector by the matrix. So if you take the matrix's row space and multiply by each of the basis vectors of the nullspace, you will get zero vectors in return (or since it was a matrix of the basis vectors to the null space, you will get the zero matrix in return).
 
Last edited:

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