Find basis B given the transition matrix and B'

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Homework Help Overview

The problem involves finding a basis B given a transition matrix P and a basis B' in R3. The transition matrix relates the two bases, and the original poster is exploring the implications of this relationship.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply a theorem regarding transition matrices and questions whether the inverse of P provides the basis B. Some participants affirm the original poster's understanding and suggest that multiplying by the inverse of P would yield the basis B.

Discussion Status

The discussion appears to be progressing positively, with participants confirming the original poster's reasoning and providing supportive feedback regarding the use of the inverse of the transition matrix.

Contextual Notes

The original poster expresses uncertainty about their understanding and seeks validation of their approach, indicating a learning process in understanding transition matrices and basis transformations.

fattycakez
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Homework Statement


The Matrix P =
1 0 3
1 1 0
0 3 1
is the transition matrix from what basis B to the basis B' = {(1,0,0),(1,1,0),(1,1,1) for R3?

Homework Equations


[v]B=P[v]B'

The Attempt at a Solution


I'm looking at a theorem in my book that says

" if P is the transition matrix from a basis B' to a basis B for a finite-dimensional vector space V, then P is invertible and P-1 is the transition matrix from B to B'. "

So does the inverse of P give the basis B? Please tell me how wrong I am :)
 
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I will gladly tell you how wrong you are. Not at all (if I understand you correctly)
You have ## \bf{P} \cdot \bf{B} = \bf{B'} ## Multiply both sides by ## \bf{P}^{-1} ## and you have solved your equation for B.
 
BiGyElLoWhAt said:
I will gladly tell you how wrong you are. Not at all (if I understand you correctly)
You have ## \bf{P} \cdot \bf{B} = \bf{B'} ## Multiply both sides by ## \bf{P}^{-1} ## and you have solved your equation for B.
Awesome, thank you! \m/
 
No problemo
 

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