How Far Must Point P Be from Speaker A for Constructive Interference at 400 Hz?

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To achieve constructive interference at point P from speakers A and B emitting sound at 400 Hz, the wavelength (λ) is calculated as 0.85 m using the formula λ = v/f, where v is the speed of sound (340 m/s). The condition for constructive interference is given by the equation λ = 2ΔL/(2p-1), where ΔL represents the path difference. The lowest order of constructive interference occurs at p = 1, leading to a path difference of 0.85 m. However, there is a suggestion that the nearest node to speaker A may not correspond to this lowest order, indicating further analysis may be needed.
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Homework Statement



Two speakers A and B, sends out sounds at 400 hz

In what distance x between speaker A and the point P is it constructive interference ?

http://s716.photobucket.com/user/Pitoraq/media/Fys2121_zps9a68fef2.png.html

Homework Equations




λ = 2ΔL/(2p-1),

v = 340 m/s

f = 400 Hz

The Attempt at a Solution



λ = 2ΔL/(2p-1),

λ = 340/400 = 0.85 m <==>

lowest constructive interference p = 1

0.85 m = ΔL <==>

0.85 = y - x, where y = (2.5)^2+x^2=y^2 is the distance between P and B.

Is this right ?
 
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That should get you a constructive interference point (node).
I don't think the nearest node to A (i.e., smallest x) occurs for p = 1, though.
 
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