Continuity and intermediate value theorem

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SUMMARY

The discussion focuses on the application of the Intermediate Value Theorem (IVT) to prove that if a continuous function g: [x,y] → R has a value k strictly between g(x) and g(y), and g⁻¹(k) contains at least two elements, then there exists a value m strictly between g(x) and g(y) such that g⁻¹(m) contains at least three elements. The participants emphasize the importance of visualizing the function and its graph to understand the behavior of g and the implications of the IVT in this context.

PREREQUISITES
  • Understanding of the Intermediate Value Theorem (IVT)
  • Familiarity with continuous functions in real analysis
  • Basic graphing skills for visualizing functions
  • Knowledge of inverse functions and their properties
NEXT STEPS
  • Study the proof of the Intermediate Value Theorem in detail
  • Explore examples of continuous functions and their graphs
  • Learn about the properties of inverse functions in real analysis
  • Practice visualizing function behavior with graphing tools
USEFUL FOR

Students of calculus, mathematicians interested in real analysis, and educators seeking to illustrate the Intermediate Value Theorem and its applications in function behavior.

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let [x,y] be in R and be a closed bounded interval and let g: [x,y] --> R be a function. suppose g is continuous. let k exist in R. suppose that k is strictly between g(x) and g(y) and that g-1(k) has at least 2 elements. prove that there is some m that is strictly between g(x) and g(y) and that g-1(m) has at least three elements.

i can't visualize this (i.e. with just 2 elements for g-1(k)). i know i need to use intermediate value theorem but can't come up with anything concrete.
 
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please help...
 
i can't visualize this (i.e. with just 2 elements for g-1(k))

Start by drawing a picture. Pick where g(x) and g(y) are, and pick two points that have the same y-value in between x and y. Then start drawing a couple of graphs
 

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