Continuous => limited in region

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Homework Help Overview

The problem involves demonstrating that a continuous function f: R -> R is bounded in a neighborhood of a point x'. The discussion centers around the implications of continuity and the definitions involved in the context of this problem.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of a specific inequality related to continuity and question the meaning of "limited in a suitable environment." There is an exploration of how to apply the epsilon-delta definition of continuity to establish boundedness.

Discussion Status

The discussion is ongoing, with participants clarifying terminology and exploring the implications of continuity. Some guidance has been offered regarding the use of inequalities to establish boundedness, but no consensus has been reached on the approach to take.

Contextual Notes

There is a mention of non-standard terminology, specifically "limited in a suitable environment," which some participants interpret as "bounded in some neighborhood." This indicates a potential area of confusion that may affect the discussion.

Kruger
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Homework Statement



I've to show that if f:R->R is continuous in x' then f is limited in a suitable environment of x'.

2. The attempt at a solution

My lecturer said we should use the following inequality

|f(a)|=<|f(a)-f(y)|+|f(y)|

But how should I go on, I know I have to show something like this:

It exists d>0: it exist c element of [x'-d, x'+d]=I ==> |f(x)|=<|f(c)| for every x in I.

But how should I go on?
 
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Always include relevant definitions. "limited in a suitable environment" is not standard terminology, and I don't know what it means. It sounds like "bounded in some neighborhood", but this would follow imediately from the epsilon delta definition of continuity.
 
I thought that, too. I mean that it follows imidiately, but our lecturer said that we've to take |f(a)|=<|f(a)-f(y)|+|f(y)| to show that.

With limited in a suitable environment it is ment what you said (bounded in some neightboorhood).
 
Right, so pick any e>0, then a d>0 so that |y-a|<d => |f(y)-f(a)|<e, and then use that inequality to show there is an M with |f(y)|<M, all y in some neighborhood of a.
 

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