Contour Integration for the Complex Contour Integral Problem

[ijustlost]

I'm trying to find

<br /> \int_{-\infty}^{\infty} \frac{exp(ax)}{cosh(x)} dx<br />

where 0<a<1 and x is taken to be real. I'm doing this by contour integration using a contour with corners +- R, +- R + i(pi), and I'm getting an imaginary answer which is

\frac{2i\pi}{sin (a \pi)}.

I'm thinking this is a problem because my original integral was completely real. Can I just take the real part of my answer, and say the integral = 0 ? That doesn't seem to make any sense, I've drawn a graph of the function and it doesn't look like it's integral should be zero! I'm fairly sure my answer to the contour integral is correct!

 

[ijustlost]

P.s - is there a guide to using tex on physics forums somewhere? Then I could format the above properly!

 

[malawi_glenn]

Math & Science Tutorials --> Introducing LaTeX Math Typesetting

 

[ijustlost]

Ah thanks, I knew there was one somewhere!

 

[ijustlost]

Oops, stupid me! The answer is

<br /> \frac{\pi}{cos(\frac{a\pi}{2})}<br />

I didn't work out the phase shift the function takes on along the top line of the path properly!