Contradiction of statement regarding monotonicity

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SUMMARY

The discussion centers on the mathematical statement regarding the monotonicity of functions defined as f(x) > 0 for x > 0 and the limit condition lim_{x→∞} f(x) = 0. The provided counterexample f(x) = \twopartdef { \frac{1}{2x} } {x rational} {\frac{1}{x}} {x irrational} effectively demonstrates that the statement can be contradicted. Another proposed example, f(x) = \frac{sin(x)+2}{x^2}, also serves to illustrate the concept, although it requires further justification to confirm it is not strictly decreasing for sufficiently large x.

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oferon
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Hi all!
We were given to proove or falsify the following statement:

Given f(x)>0 \,\ ,\,x>0 \,\,\,\,,\lim_{x\to\infty}f(x)=0
Then f(x) is strictly decreasing at certain aεℝ for every x>a

Now in their solution they contradicted the statement with:
\newcommand{\twopartdef}[4]<br /> {<br /> \left\{<br /> \begin{array}{ll}<br /> #1 &amp; \mbox{if } #2 \\<br /> #3 &amp; \mbox{if } #4<br /> \end{array}<br /> \right. } f(x) = \twopartdef { \frac{1}{2x} } {x \,\,\, rational} {\frac{1}{x}} {x \,\,\, irrational}

Now i thought of another one: f(x)=\frac{sin(x)+2}{x^2}
Is that a good example? Thank you!
 
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oferon said:
Hi all!
We were given to proove or falsify the following statement:

Given f(x)&gt;0 \,\ ,\,x&gt;0 \,\,\,\,,\lim_{x\to\infty}f(x)=0
Then f(x) is strictly decreasing at certain aεℝ for every x>a

Now in their solution they contradicted the statement with:
\newcommand{\twopartdef}[4]<br /> {<br /> \left\{<br /> \begin{array}{ll}<br /> #1 &amp; \mbox{if } #2 \\<br /> #3 &amp; \mbox{if } #4<br /> \end{array}<br /> \right. } f(x) = \twopartdef { \frac{1}{2x} } {x \,\,\, rational} {\frac{1}{x}} {x \,\,\, irrational}

Now i thought of another one: f(x)=\frac{sin(x)+2}{x^2}
Is that a good example? Thank you!

Yes, that's a nice example too. If it is something to hand in you would want to include an argument to show that it isn't strictly decreasing for x large enough.
 
Will do. Thank you!
 

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