Convergence for a series: what is wrong with my method?

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SUMMARY

The discussion focuses on the convergence of a series defined by the nth term \( a_n = \frac{(-1)^{n+1}(2n+1)^n}{n(n+1)} \). Participants clarify that \( S_n \) represents the partial sum of the series, and \( R_n \) is the remainder defined as \( R_n = S - S_n \). The limit of \( S_n \) as \( n \to \infty \) is debated, with suggestions that it may not converge to 3 or -1 without proper justification. The necessity of verifying whether \( a_n \) approaches 0 is emphasized as a critical step in determining convergence.

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JJHK
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Convergence for a series: what is wrong with my method??

Homework Statement



For the following series, write formulas for the sequence an, Sn, and Rn, and find the limits of the sequences as n→∞.

Homework Equations



Sn is the partial sum of the series.

Rn is the remainder and is given by
Rn = S - Sn,
where
lim(n→∞) Sn = S



The Attempt at a Solution



an is pretty straightforward...

an = Ʃ(1→∞) (-1)n+1 (2n+1)n / [ (n) (n+1) ]

and as n→∞, an → 0

For Sn, I am getting:

Sn = 3 / (1x2) - 5 / (2x3) + 7 / (3x4) - 9 /(4x5) + ...

= 3 (1/1 - 1/2) - 5 (1/2 - 1/3) + 7(1/3 - 1/4) - 9 (1/4 - 1/5) + ...

= 3 - 1/2 (3+5) + 1/3 (5+7) - 1/4 (7+9) + ...

= 3 - 8/2 + 12/3 -16/4 + ...

= 3 - 4 + 4 - 4 + ...

= 3 + Ʃ(1→∞) (-1)nx4

so as n→∞, does Sn approach 3 or -1, or neither?

Also, what would Rn be?

thank you so much!
 
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JJHK said:

Homework Statement



For the following series, write formulas for the sequence an, Sn, and Rn, and find the limits of the sequences as n→∞.

Homework Equations



Sn is the partial sum of the series.

Rn is the remainder and is given by
Rn = S - Sn,
where
lim(n→∞) Sn = S



The Attempt at a Solution



an is pretty straightforward...

an = Ʃ(1→∞) (-1)n+1 (2n+1)n / [ (n) (n+1) ]

That is not ##a_n##. What you have on the right is ##S##, assuming the series converges.
and as n→∞, an → 0

##a_n## is the nth term of the series$$
a_n=\frac{-1^n(2n+1)^n}{n(n+1)}$$Unless you have mistyped the problem, I don't think you will find ##a_n\rightarrow 0##. In any case you haven't shown any argument.
For Sn, I am getting:

Sn = 3 / (1x2) - 5 / (2x3) + 7 / (3x4) - 9 /(4x5) + ...

= 3 (1/1 - 1/2) - 5 (1/2 - 1/3) + 7(1/3 - 1/4) - 9 (1/4 - 1/5) + ...

= 3 - 1/2 (3+5) + 1/3 (5+7) - 1/4 (7+9) + ...

= 3 - 8/2 + 12/3 -16/4 + ...

= 3 - 4 + 4 - 4 + ...

= 3 + Ʃ(1→∞) (-1)nx4

so as n→∞, does Sn approach 3 or -1, or neither?

Also, what would Rn be?

thank you so much!

##S_n## is the sum of the first ##n## terms. The expression for ##S_n## would never end with a "...". You can't calculate ##S## or ##R_n=S-S_n## unless the series converges. Go back to the beginning and make sure you copied the problem correctly and start by proving whether or not ##a_n\rightarrow 0##.
 

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