Since an --> 0, given some epsilon>0, there exists and m>0 such that /an-0/=/an/<epsilon for all n>m
thus, /bn-b/</an/<epsilon for all n>m
therefore, by definition bn-->b
Since an --> 0, given some epsilon>0, there exists and m>0 such that /an-0/=/an/<epsilon for all n>m
thus, /bn-b/</an/<epsilon for all n>m
therefore, by definition bn-->b