Convergence of a functional series (analysis)

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Homework Help Overview

The discussion revolves around the convergence properties of a functional series defined as \(\sum_{n=1}^\infty \frac{x}{n}\) for \(x \in \mathbb{R}\). Participants are exploring whether this series is pointwise and/or uniformly convergent.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the divergence of the harmonic series and its implications for the convergence of the given functional series. There are considerations about the behavior of the series at specific points, particularly at \(x = 0\), and how this affects the overall classification of convergence.

Discussion Status

Some participants have provided insights regarding the convergence at specific points, noting that the series converges at \(x = 0\) while diverging for other values of \(x\). There is an ongoing exploration of the terminology related to convergence and divergence in this context.

Contextual Notes

Participants are questioning the implications of convergence at isolated points versus the overall behavior of the series across its domain. The discussion reflects a need for clarity on definitions and classifications of convergence in functional series.

mred11
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Homework Statement



Determine whether the following functional series is pointwise and/or uniformly convergent:

[itex]\sum_{n=1}^\infty \frac{x}{n} (x\in\mathbb{R})[/itex]

Homework Equations



The Attempt at a Solution



My answer to this seems very straightforward and I would be very grateful if someone could let me know if the method is correct. We can re-write the series as:

[itex]x \sum_{n=1}^\infty \frac{1}{n}[/itex]

We know the harmonic series (of numbers) [itex]\sum_{n=1}^\infty \frac{1}{n}[/itex] is divergent, so therefore the series cannot be pointwise or uniformly convergent.

Is this correct? Thanks!
 
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You could also use the p-series test to arrive at the same conclusion.
 
Thanks. I just noticed something: if x=0, then the series is just zero, so it converges. Given that the series isn't convergent for *all* values of x in the domain, is it still correct to say the functional series is divergent? I suppose it's a question of terminology. Thanks for the help.
 
mred11 said:
Thanks. I just noticed something: if x=0, then the series is just zero, so it converges. Given that the series isn't convergent for *all* values of x in the domain, is it still correct to say the functional series is divergent?

It's pointwise convergent at points where it converges, and pointwise divergent where it doesn't converge.
 
mred11 said:
Determine whether the following functional series is pointwise and/or uniformly convergent:

Based on your question, i would say that the correct answer is: point-wise convergent at x = 0. (which would imply that at any other values of x, the series is divergent)
 
Ok, thanks!
 

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