Convergence of ln(x)/x^1.0001 Series - Finding the Integral

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SUMMARY

The discussion focuses on determining the convergence of the series defined by the term ln(x)/x^1.0001 as x approaches infinity. Participants agree that the integral test is the most appropriate method for this analysis. It is established that the logarithmic function ln(x) grows slower than any positive power of x, which indicates that the series diverges. The integral of ln(x)/x^1.0001 confirms this conclusion, reinforcing the divergence of the series.

PREREQUISITES
  • Understanding of series convergence tests, including the integral test and comparison test.
  • Familiarity with logarithmic functions and their growth rates.
  • Basic knowledge of limits and behavior of functions as x approaches infinity.
  • Ability to compute integrals involving logarithmic expressions.
NEXT STEPS
  • Study the Integral Test for convergence in detail.
  • Explore the Comparison Test and its applications in series analysis.
  • Learn about the behavior of logarithmic functions relative to polynomial functions.
  • Practice solving integrals involving logarithmic terms to solidify understanding.
USEFUL FOR

Students studying calculus, particularly those focusing on series convergence, as well as educators teaching convergence tests and integral calculus.

Frillth
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Homework Statement



For this problem, I need to determine whether a series with the general term ln(x)/x^1.0001 will converge from x=1 to x=infinity.

Homework Equations



I'm not quite sure what the relevant equations would be for this, but I'm supposed to use one of the series convergence tests, like the ratio test, root test, integral test, comparison test, or limit comparison test.

The Attempt at a Solution



It seems like the integral test should apply to this problem, but for some reason I can't find the integral.
 
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Well, you know that the series will diverge or converge with the associated integral, right?
Also remember that the logarithm of x grows slower to infinity than ANY positive power of x does.
 

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