Convergence of Summation n/e^n using L'Hospital's Rule | Homework Help

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The discussion centers on determining the convergence of the series Ʃ n/e^n using L'Hospital's Rule and the ratio test. Initially, the user attempted to apply the integral test but encountered an infinity-infinity form, prompting the need for L'Hospital's Rule. After some clarification regarding the integral setup, the user shifted to the ratio test, which ultimately indicated that the series converges since the limit of the ratio is 1/e, less than 1. The conversation highlights the importance of correctly applying calculus techniques to analyze series convergence. The conclusion confirms that the series converges based on the ratio test results.
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Homework Statement


Ʃ n/e^n converge or diverge


Homework Equations





The Attempt at a Solution



I got this down to an improper integral using the integral test but I am weak at L'Hospitals rules and I was wondering if someone could help me out

I have

\int n/e^n from 1 to infinity

down to

Limit b to infinity ne^n - e^n |from 1 to b

this gives me infinity - infinity so time for L'Hospitals ( forgive my spelling)
I know to divide by the recripical of either one but I get stuck from there
 
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It's probably easier to use the ratio test. If you have to use the integral test you didn't get the integral quite right. There's a sign problem (which isn't terribly important) and don't you mean e^(-n) in the integral (which is terribly important)?
 
ok i will try the ratio test for this... I am studying for a test and have already worked this problem and turned it in when I got it back graded the only comments were that it was infinity-infinity and needs L'Hospitals rule. I had originally put infinity - infinity so it diverges. The original problem is correct it is n / e^n not e ^-n
 
EEintraining said:
ok i will try the ratio test for this... I am studying for a test and have already worked this problem and turned it in when I got it back graded the only comments were that it was infinity-infinity and needs L'Hospitals rule. I had originally put infinity - infinity so it diverges. The original problem is correct it is n / e^n not e ^-n

No, I meant your integral should have been -n/e^n - 1/e^n or -ne^(-n) - e^(-n). It's not infinity-infinity.
 
Ok I did the Ratio test could you please check my work?

\frac{n}{e^n}

\frac{n+1}{e^(n+1)} * \frac{e^n}{n}

so all e's cancel except 1 giving me

\frac{n+1}{e*n} the limit of this is ∞/∞ with L'Hopitals i have

\frac{1}{e} which is less then 1 so ratio test says converges
 
Last edited:
Yes, the limit of the ratio is 1/e so it converges.
 
Awesome thanks... and I will try to work on form... that was the edited version you should have seen what i had first lol!
 

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