Convergence Proof for Continuous Functions with Second Derivative at Zero

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Homework Statement



let f be a continuous function on an interval around 0, and let an=f(1/n) (for large enough n). prove that if f''(0) exists and f'(0)=f(0)=0, then
conv-1.jpg
converges

Homework Equations



i proved earlier in the problem that if the series converges, f(0)=0, and if f'(0) exists and the series converges, then f'(0)=0

The Attempt at a Solution


not really sure how to approach this. don't know if a convergence test should be used, but i know that lim n->infinity an=0 (zero test is inconclusive). what should i do?
 
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so you know
f(0) = 0

f'(0) = lim x->0, f(x)/x = 0

f''(0) = lim x->0, f'(x)/x = a

the 2nd line shows, f(x) tends to zero faster than x...
 
i'm not really sure how that helps. that takes me back to the result of the zero test, and the fact that f'(0)=0, which i already proved. how does that pertain to the series.
 
how about working towards a comparison test...? as f(x)/x tends to zero, near 0, maybe you can do something with f(1/n)/(1/n)