Convergent Telescoping Sum with Bounded Sequences (a_n) and (b_n)

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Homework Help Overview

The discussion revolves around the convergence of the series \(\sum |x_n - x_{n+1}|\), where \(x_n = a_n + b_n\) with \((a_n)\) being a bounded decreasing sequence and \((b_n)\) a bounded increasing sequence. Participants explore the properties of these sequences and their implications for the convergence of the sum.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the triangle inequality and consider different groupings of terms. There is an exploration of the implications of bounded monotonic sequences and the conditions under which the series converges.

Discussion Status

The discussion is active, with participants questioning the application of the triangle inequality and the convergence of the right-hand side. Some participants suggest that removing absolute values could lead to a telescoping sum, while others are seeking clarification on the convergence criteria.

Contextual Notes

There is an acknowledgment that showing terms of the series approach zero is not sufficient for convergence, and the discussion includes considerations of the bounded nature of the sequences involved.

Treadstone 71
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"Let (a_n) be bounded decreasing and (b_n) be bounded increasing sequences. Let x_n =a_n+b_n. Show that [tex]\sum|x_n-x_{n+1}|[/tex] converges."

This ALMOST is a telescoping sum, but it doesn't work since if I try to use the triangle inequality, the sum I want is on the greater side. Ratio test, root test, etc all fail since there is insufficient information.
 
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How did you try to apply the triangle inequality? Try different groupings of the terms.
 
By the triangle inequality,

[tex]\sum|x_n-x_{n+1}| = \sum|a_n+b_n-(a_{n+1}+b_{n+1})| \leq \sum|a_n-a_{n+1}|+\sum|b_n-b_{n+1}|[/tex]​

also, bounded monotonic sequences are convergent.
 
They are indeed convergent, but showing that the terms of the series go to 0 is insufficient to show that it converges. If we remove the absolute value signs, it becomes a telescoping sum and therefore it converges. Knowing that, and that an, bn converge, can we conclude something from it?
 
Treadstone 71 said:
They are indeed convergent, but showing that the terms of the series go to 0 is insufficient to show that it converges. If we remove the absolute value signs, it becomes a telescoping sum and therefore it converges. Knowing that, and that an, bn converge, can we conclude something from it?

Yes, you will have shown the right hand side converges to a finite value. The left hand side has positive terms and is then bounded above, so?
 
How did you conclude that the RHS converges?
 
Nevermind, I figured it out, thanks.
 

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