Converging Complex Series: Finding Limits and Sums

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SUMMARY

The forum discussion centers on finding limits and sums of complex series, specifically focusing on two series: the first being the geometric series \(\sum (n = 0 \text{ to } ∞) (-1)^{n}(\frac{2}{3})^{n}\) and the second, a more complex series \(\sum(k = 1 \text{ to } ∞) \frac{(-1)^{k}k^{3}}{(1+i)^{k}}\). The first series converges with a limit of \(\frac{3}{5}\) after being rewritten as \(\sum (-\frac{2}{3})^{n}\). The second series presents challenges due to its complexity and the inapplicability of the root test.

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Hercuflea
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Homework Statement



pardon my terrible latex skills

Find the limit of this series:

[itex]\sum[/itex] (n = 0 to ∞) (-1)[itex]^{n}[/itex]([itex]\frac{2}{3}[/itex])[itex]^{n}[/itex]

Homework Equations



No idea, it looks like an alternating series test, but I am supposed to actually find the sum, not just whether or not it converges.

The Attempt at a Solution



No idea


Homework Statement



[itex]\sum[/itex](k = 1 to ∞) [itex]\frac{(-1)^{k}k^{3}}{(1+i)^{k}}[/itex]

Homework Equations






The Attempt at a Solution



Once again, it looks like an alternating series. I tried the root test and got (1/2)-(1/2)i, but then I realized the root test is not applicable because the series is complex. No way to compare (1/2) - (1/2)i to the real number 1 in terms of ordering. Its not geometric so I don't have a formula for finding the sum.
 
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Found the answer to the first problem,

Its a geometric series if you rewrite as Ʃ (-2/3)^n

Ratio is (-2/3) so the limit is 1/(1+2/3) = 3/5

I still have no idea how to do the second problem
 

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