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omartech
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Homework Statement
a projectile of mass M explodes into three fragments while in flight at velocity v. one fragment of mass M/2 travels in the original direction, one of mass 3M/10 comes to rest and the third fragment of mass M/5 travels in the opposite direction. The energy released in the explosion equals to 4.75 times the kinetic energy of the projectile before explosion. What are the velocities of the fragments?
Homework Equations
according to my calculations,
Mv (momentum before explosion) = M/2*v1 + M/5*v2 ... since 3M/10 comes to rest. its velocity is zero.
and .. for kinetic energy,
1/2 Mv^2 * 4.75 = 1/2 M/2 *v1^2 + 1/2 M/5 *v2^2.
from these equations we get,
v = v1/2 + v2/5 and 4.75v^2 = v1^2/4 + v2^2/10
Now.. how are these to be solved? in terms of v?
The Attempt at a Solution
I hope the formation of the above two equations is correct?