I Conversion factors derivation.

AI Thread Summary
The discussion focuses on the conversion formulas between the MKS and CGS systems for force and work, highlighting that 1 Newton equals 10^5 dynes and 1 Joule equals 10^7 ergs. It emphasizes the dimensional analysis of force and energy, where force is expressed as M L T−2 and energy as M L² T−2. Additionally, it addresses the conversion of CGS units, specifying that centimeters convert to meters and grams convert to kilograms in the MKSA system. Understanding these conversions is crucial for accurate scientific calculations across different measurement systems. The conversation underscores the importance of dimensional consistency in physics.
akerkarprashant
Messages
74
Reaction score
10
TL;DR Summary
Conversion factors derivation.
Queries regarding MKS to CGS system for the following formulas.

Force - Newton (MKS), Dynes (CGS)
Work - Joule (MKS), Ergs (CGS)

1N = 10^5 dynes.
1J = 10^7 ergs.

How the above unit conversion formulas are derived ?
 

Attachments

  • Conversion factors.jpg
    Conversion factors.jpg
    26.7 KB · Views: 140
Physics news on Phys.org
Look at the dimensions of force and energy.
force = M L T−2
energy = M L2 T−2

Convert CGS cm to MKSA metres.
Convert CGS gram to MKSA kg.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top