Convert 4-Bit Binary Number to Decimal in Java

  • Context: Java 
  • Thread starter Thread starter J.live
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SUMMARY

The discussion focuses on converting a four-bit binary number to a decimal integer using Java. Participants emphasize the importance of reading the binary input as a string and utilizing the charAt method to access individual bits. Key insights include the necessity of subtracting the character '0' from the binary digits to convert them from characters to integers. The final solution involves calculating the decimal value by multiplying each bit by its corresponding power of two based on its position in the string.

PREREQUISITES
  • Understanding of Java programming language
  • Familiarity with string manipulation methods in Java, specifically charAt
  • Basic knowledge of binary number representation and conversion to decimal
  • Awareness of ASCII values and character arithmetic
NEXT STEPS
  • Implement error handling for binary input validation in Java
  • Explore the Integer.parseInt method for binary to decimal conversion
  • Learn about bitwise operations in Java for more efficient calculations
  • Study the use of loops in Java for processing variable-length binary strings
USEFUL FOR

Java developers, computer science students, and anyone interested in understanding binary number manipulation and conversion techniques in programming.

  • #31
hey J.live
I am currently working on this problem as well. I've tried your code but i keep getting an error for the code line:

number=keyboard.nextLine();
number=keyboard.nextLine();

do you know why by any chance?
 
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  • #32
Mark44 said:
Here's the code with the extra input line removed, and using the += operator, plus the addition of some white space for better readability.
Code:
int value;
String number;
				
		 	     
System.out.print("Enter Number ");
number = keyboard.nextLine();
		 		
value=0;
value += (number.charAt(0) - '0') * 8;
value += (number.charAt(1) - '0') * 4;
value += (number.charAt(2) - '0') * 2;
value += (number.charAt(3) - '0') * 1;

System.out.println(value);
hey Mark44
I am currently working on this problem as well. I've tried your code but i keep getting an error for the code line:

number=keyboard.nextLine();
number=keyboard.nextLine();

do you know why by any chance?
 
  • #33
Why do you have two lines there?

Show us your code and I'm sure we can figure it out.
 
  • #34
my codes are:


import java.util.Scanner;

public class project11p117 {
Scanner input = new Scanner(System.in);
public static void main(String [] args){

int value;
String number;


System.out.print("Enter Number");
number=keyboard.nextLine();


value=0;
value= value+(number.charAt(0)-'0')*8;
value=value+(number.charAt(1)-'0')*4;
value=value+(number.charAt(2)-'0')*2;
value=value+(number.charAt(3)-'0')*1;

System.out.println(value);

}
}
 
  • #35
my codes are:import java.util.Scanner;

public class project11p117 {
Scanner input = new Scanner(System.in);
public static void main(String [] args){

int value;
String number;System.out.print("Enter Number");
number=keyboard.nextLine();value=0;
value= value+(number.charAt(0)-'0')*8;
value=value+(number.charAt(1)-'0')*4;
value=value+(number.charAt(2)-'0')*2;
value=value+(number.charAt(3)-'0')*1;

System.out.println(value);

}
}
 

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