Converting 2D density (circle) to 3D density (sphere)

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SUMMARY

This discussion focuses on converting 2D density (objects per area) in a circle to 3D density (objects per volume) in a sphere, specifically for scenarios involving crabs and fish foraging on plankton. The crab operates in a 2D detection area defined by ∏*acuity², while the fish operates in a 3D detection volume defined by (4/3)*∏*acuity³. Key considerations include the differences in prey distribution in water versus land environments and the implications of the "Curse of Dimensionality" on density calculations.

PREREQUISITES
  • Understanding of geometric formulas for area and volume
  • Familiarity with the concept of prey density in ecological studies
  • Knowledge of the "Curse of Dimensionality" and its implications
  • Basic principles of spatial foraging behavior in aquatic and terrestrial environments
NEXT STEPS
  • Research geometric conversions between 2D and 3D densities
  • Explore ecological modeling techniques for prey distribution
  • Study the "Curse of Dimensionality" in depth and its effects on data analysis
  • Investigate spatial foraging strategies of aquatic versus terrestrial species
USEFUL FOR

Ecologists, marine biologists, and researchers studying foraging behavior and prey distribution in different environments will benefit from this discussion.

Jimbo2
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Hi All,
I'm looking for help in converting 2D density (objects/area) in a circle to 3D density (objects/volume) in a sphere, the circle and sphere having the same radius and distribution of objects being uniform.

To make this problem more intuitive, here's a sample application: both crabs and fish forage on the same plankton in the water column. The crab can only access plankton as he walks on the ground (i.e., he forages in 2D space), but the fish can access the plankton in the water column (i.e., he forages in 3D space). The crab has a detection area of ∏*acuity^2 while the fish has a detection volume of (4/3)*∏*acuity^3. Given a prey density, can the number of prey within the 2D detection zone be converted to the number of prey within the 3D detection zone (or vice versa)? I may be overthinking this, but help is much appreciated! Thanks!
 
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In your concrete example, the crab's feeding zone isn't really 2D - it's a thin sheet. Since the crab's detection range in the vertical direction can taken to extend right through th sheet you can treat it as 2D. But maybe this isn't really the scenario that you want to apply it to.
 
In addition to what haruspex mentioned, one thing you should consider is the differences in the situations of depth (like water) and area (like land) with regards to the densities.

For example, the water based situation will have densities that will most likely be a lot sparser and weirdly distributed in land.

It's called the "Curse Of Dimensionality":

http://en.wikipedia.org/wiki/Curse_of_dimensionality
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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