Converting an nth order equation to a system of first order equations

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Homework Help Overview

The problem involves converting a second-order differential equation, specifically \(y'' + x^2y' + 12y = 0\), into a system of first-order equations. The initial conditions provided are \(y(0) = 0\) and \(y'(0) = 7\).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss isolating the highest derivative and defining new variables \(u_1\) and \(u_2\) to represent \(y\) and \(y'\). There is exploration of expressing the system in matrix form and questions about how to incorporate initial conditions into the vector form.

Discussion Status

Some participants indicate that the conversion to a system of first-order equations has been successfully achieved. There is ongoing clarification regarding the representation of initial conditions in the context of the defined variables. Multiple interpretations of the matrix representation and the initial conditions are being explored.

Contextual Notes

Participants note that the professor's instructions included finding the vector corresponding to the initial conditions, which adds complexity to the discussion. There is acknowledgment of potential confusion stemming from the professor's notes.

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Homework Statement


convert y'' +x^2y'+12y=0 to a system of first order equations with initial conditions y(0)=0 y'(0)=7.


Homework Equations





The Attempt at a Solution


first i isolate highest derivative y'' = -x^2y'-12y
then i let u_1=y u_2=y'

then (u_1)' = u_2 and (u_2)= y''

then (u_2)' = (-12u_1)-(x^2u_2)

i then write these as

(u_1)' = 0*u_1 + 1u_2
(u_2)' = (-12u_1) + (-x^2u_2)


so then in matrix form i have

matrix [u_1 u_2] = [top -0 1 bottom -12 -x^2] *[u_1 u_2] + [0 0]

i think I am close but i don't know how to get vector c but putting vec u(0) ...pls help and sorry for the poor notation...i can rewrite but i can't find link to use the symbols and such
 
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bump...pleaseee help
 
I think you've basically got it. [u1,u2]'=[[0,1],[-12,-x^2]]*[u1,u2]. You can add [0,0] to that but there's no need to. The initial condition is then [u1(0),u2(0)]=[0,7], right? If you want some texing clues check out https://www.physicsforums.com/showthread.php?t=8997
 
im sorry but if u can, please help me with that matrix algebra...my prof just copied chicken scratch notes and didn't explain anything.

edit :this is what i get

[u1,u2]'= [top 0 u1 bottom -12u2 -x^2u2]

how to i get my final answer
 
Last edited:
There's not much to explain. The problem was to convert the problem to a system of first order ode's. You have already done that, I think. It didn't say you should solve it, right? It just said convert.
 
your right, it says to convert, but my prof also wants us to find vector c with the initial conditions (forgot to mention). that's how I am not sure you get [0,7] which is the correct answer
 
[u1(0),u2(0)]=[y(0),y'(0)], that was your definition of u1 and u2, right?
 
yes.
 
hachi_roku said:
yes.

Ok, so I'm guessing you also see why that's [0,7].
 
  • #10
ok i think i get it... the y values from the initial conditions are the ones put in the vector c matrix
 
  • #11
got it thanks!
 

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