PDE: Solving to find a constant c

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SUMMARY

The discussion focuses on solving the nonlinear ordinary differential equation u' = u(1-u) by analyzing specific solutions u_1(x) = e^x/(1+e^x) and u_2(x) = 1. It is established that both u_1 and u_2 are valid solutions, while their sum u_1 + u_2 is not. The values of the constant c for which cu_1 and cu_2 are solutions are determined to be c = 0 or c = 1, confirming that these are the only valid constants for the given equation.

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Homework Statement


Consider the nonlinear (ordinary) differential equation u' = u(1-u).
a) Show that u_1 (x) = e^x/(1+e^x) and u_2(x) = 1 are solutions.
b) Show that u_1+u_2 is not a solution.
c) For which values of c is cu_1 a solution? How about cu_2 ?

Homework Equations



N/a

The Attempt at a Solution



a) To show that they are a solution I plugged in the corresponding u_1 and u_2 into the equations and proved equality.
b) To show that this is not a solution, I did the same.
c) This is where I am having trouble, here is my strategy:

We observe c*u_2 first.
we know u_2' = 0 so from u'=u(1-u)
we have c*u' = 0 and we know that 1*c = c so on the right hand side we have c(1-c) and so we have:
c-c^2 =0
This means c is either 0 or 1.

This doesn't seem right, there seems to be a better way (perhaps involving differential equations knowledge) to solve for c. I would imagine c could be in the form e^x of some sort.

Similarly with c*u_1 I am finding equally difficult problems where c = 0.
 
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Substitute in the proposed solution.

Apply all the operations and simplify.

See if you can find a value of C for which the resulting equation is true.
 
So, when I solved for part c for u_2 and found that c=c^2
This means that c = 0 or 1.
That would be a correct solution then?
 

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