Converting between cartesian and polar coordinates

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SUMMARY

The discussion focuses on converting the velocity of a particle moving along the line y=2 into polar coordinates. The initial velocity is given as v = ui, and the position is expressed as r = √((ut+c)² + 4). The polar angle is calculated using φ = arctan(2/(ut+c)). The speed in polar coordinates is derived from the formula v = √((dr/dt)² + (r dφ/dt)²), highlighting the relationship between Cartesian and polar representations of motion.

PREREQUISITES
  • Understanding of Cartesian coordinates and their representation
  • Familiarity with polar coordinates and their conversion
  • Basic knowledge of calculus, specifically differentiation and integration
  • Concept of velocity and its representation in different coordinate systems
NEXT STEPS
  • Study the derivation of polar coordinates from Cartesian coordinates
  • Learn about the application of the chain rule in polar coordinate transformations
  • Explore the concept of angular velocity and its relation to linear velocity in polar coordinates
  • Investigate examples of motion in polar coordinates, including circular motion
USEFUL FOR

Students studying physics or mathematics, particularly those focusing on kinematics and coordinate transformations, as well as educators looking for examples of converting between coordinate systems.

henryc09
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Homework Statement



Particle is moving with velocity v= ui along the line y=2. What is its v in polar coordinates

Homework Equations





The Attempt at a Solution


I think I'm being really stupid here but not entirely sure where to start. If you integrate to find position you have it as = ut + c i + 2j and then in polar coordinates is this

r=[tex]\sqrt{}(ut+c)^2 + 4[/tex]r^? But then if you were to differentiate that the velocity would depend on the initial position which can't be right. I'm obviously doing something wrong and haven't got my head round this topic yet, any help would be appreciated.
 
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[tex] r=\sqrt{(ut+c)^2 + 4}[/tex]

The polar angle is:

[tex] \phi=\arctan(\frac{2}{ut+c})[/tex]

The speed in polar coordinates:

[tex] v=\sqrt{(dr/dt)^2+( r d\phi /dt)^2 }<br /> [/tex]

ehild
 

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