Converting Odd Integer Series to Sigma Notation

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SUMMARY

The forum discussion focuses on converting the integer series 2, 5, 10, 17, 26, and 37 into sigma notation. The series consists of six terms, and its pattern is derived from the addition of consecutive odd integers. The key insight is that each term can be expressed as a function of the index, specifically using the formula \( n^2 + 1 \) for \( n \) starting from 1 to 6. This allows for the series to be succinctly represented in sigma notation as \( \sum_{n=1}^{6} (n^2 + 1) \).

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brianaIScool
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1. Write each series using sigma notation.
2. The series is:

2 + 5 + 10 + 17 + 26 + 37

3. I know that above the sigma, the number is 6 because there are only six terms in the series. The trouble I seem to have with this is the fact that the series is neither arithmetic or geometric. It increases by consecutive odd integers. I don't know how to figure the notation for this series.
 
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brianaIScool said:
1. Write each series using sigma notation.



2. The series is:

2 + 5 + 10 + 17 + 26 + 37




3. I know that above the sigma, the number is 6 because there are only six terms in the series. The trouble I seem to have with this is the fact that the series is neither arithmetic or geometric. It increases by consecutive odd integers. I don't know how to figure the notation for this series.

Hint -- Each odd number can be written as twice some number plus one...
 

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