Laurent Series (Complex Analysis)

In summary, the conversation is about a student seeking help with understanding the concept and process behind attaining the Laurent series representation for a given formula in mathematical physics. They have attempted to solve several problems but have doubts about their answers and are looking for validation. The conversation also includes a discussion about a possible mistake in the calculations.
  • #1
24
5
Homework Statement
Laurent Series (Complex Analysis)
Relevant Equations
f(z) = An(z-z_o)^n
My homework is on mathematical physics and I want to know the concept behind Laurent series. I want to know clearly know the process behind attaining the series representation for the expansion in sigma notation using the formula that can be found on the attached files. There are three questions and I hope you will be able to help me in this subject matter. Thank you and God bless! This was retrieved from Charlie Harper's Analytic Method in Physics . Below is the formula needed, the problems, and the attempt to the solution.

On (a), I checked my answer with wolfram alpha however, my series representation (sigma notation) is wrong. Also in number 2, i got it wrong by using simple concept of geometric series. I believe item (c) is correct. Are my answers correct already?
 

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  • #2
Please post your working in typed form. It is easier to read and easier to reference when making comments.
It looks like your answer to a), z0=0 is ##\Sigma_0^\infty (-n+1)z^{n-1}##. Am I reading that right? It does not seem to follow from the preceding line.
 
  • #3
haruspex said:
Please post your working in typed form. It is easier to read and easier to reference when making comments.
It looks like your answer to a), z0=0 is ##\Sigma_0^\infty (-n+1)z^{n-1}##. Am I reading that right? It does not seem to follow from the preceding line.
It doesn't have a negative sign on it. The one about z_o = 1, I think it's wrong because I validated it using WolframAlpha.
 
  • #4
HansBu said:
It doesn't have a negative sign on it.
Then it's an example of why the forum rules say that images are for textbook extracts and diagrams.
 
  • #5
HansBu said:
The one about z_o = 1, I think it's wrong because I validated it using WolframAlpha.
When you introduced the (-1)n factor at the end, did you mean to switch the 1-z to z-1?
 
  • #6
haruspex said:
When you introduced the (-1)n factor at the end, did you mean to switch the 1-z to z-1?
Yes. That is what I meant. Is the math wrong?
 
  • #7
HansBu said:
Yes. That is what I meant. Is the math wrong?
What I mean is, you added the alternating sign factor but did not switch 1-z to z-1, so yes, the last line is wrong.
 

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