How can I convert sigma notation into a finite geometric series?

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A.J.710
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Homework Statement


http://postimage.org/]Screen_Shot_2015_09_14_at_4_30_06_PM.png[/PLAIN]
image url


Homework Equations


N/A

The Attempt at a Solution


I have to solve a different question using a similar method to this one but I cannot figure out how they got the sigma notation into the last equation format. I tried writing out the summation manually as well as the equation substituting n for 0,1,2,3 but they don't match up and I cannot do my next problem without figuring this one out first.
 
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A.J.710 said:

Homework Statement


Screen_Shot_2015_09_14_at_4_30_06_PM.png[/PLAIN]
image url


Homework Equations


N/A

The Attempt at a Solution


I have to solve a different question using a similar method to this one but I cannot figure out how they got the sigma notation into the last equation format. I tried writing out the summation manually as well as the equation substituting n for 0,1,2,3 but they don't match up and I cannot do my next problem without figuring this one out first.
A little context would be helpful.

What are α and β? What does u[n] represent?
 
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SteamKing said:
A little context would be helpful.

What are α and β? What does u[n] represent?

α and β are just variables, there is no value to them in the question. u[n] is a unit step function basically making the function true at n > 0 and 0 at n < 0.

The original question is a convolution question x[n] * h[n] in linear systems but what is in the picture is all that is really involved. There is nothing else too it I could post.
 
In the summation, you have ##(\frac{\alpha}{\beta})^0 + (\frac{\alpha}{\beta})^1 + (\frac{\alpha}{\beta})^2 + \dots + (\frac{\alpha}{\beta})^n ##, which is a finite geometric series with n + 1 terms. There's a formula for the sum of a geometric series.