Converting Series for Comparison Test

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SUMMARY

The discussion focuses on converting the series term $$\frac{1}{2^{n+1}}$$ into a form suitable for the comparison test in series convergence analysis. The correct transformation is demonstrated as follows: $$\frac{1}{2^{n+1}}=\frac{1}{2\cdot 2^n}=\frac{1}{2}\frac{1}{2^n}=\frac{1}{2}\left(\frac{1}{2}\right)^n$$. This conversion is essential for applying the comparison test effectively.

PREREQUISITES
  • Understanding of series convergence and divergence
  • Familiarity with the comparison test in calculus
  • Basic algebraic manipulation of exponential expressions
  • Knowledge of sequences and series notation
NEXT STEPS
  • Study the comparison test for series convergence in detail
  • Explore examples of series that converge and diverge
  • Learn about other convergence tests such as the ratio test and root test
  • Practice algebraic manipulation of series terms for clearer comparisons
USEFUL FOR

Students and educators in calculus, mathematicians analyzing series, and anyone preparing for advanced mathematics or engineering courses.

uzman1243
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I'm trying to find if this series converges or diverges using the comparison test:
attachment.php?attachmentid=70324&stc=1&d=1401850854.png


and the answer goes:
attachment.php?attachmentid=70325&stc=1&d=1401850854.png
My problem is, I am not sure how to go from 1/2^(n+1) to 1/2(1/2)^n.

can you please explain that to me
 

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$$\frac{1}{2^{n+1}}=\frac{1}{2\cdot 2^n}=\frac{1}{2}\frac{1}{2^n}=\frac{1}{2}\left(\frac{1}{2}\right)^n$$
 
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