Coordinate Distance Calculation

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Homework Help Overview

The discussion revolves around calculating the distance between two points in three-dimensional space, specifically points J(3, 7, 3) and Q(1, 2, 3). Participants explore whether simply subtracting the corresponding components of these points is a valid method for finding the distance between them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions if subtracting the coordinates directly can yield the distance. Some participants confirm that the difference J - Q results in a vector, and they discuss the relationship between this vector and the distance calculation.

Discussion Status

Participants have provided guidance on the validity of subtracting components to find the displacement vector. There is an acknowledgment that this method leads to the same result as the distance formula, but the discussion remains open regarding the conceptual understanding of these operations.

Contextual Notes

There is an indication that the original poster is referencing a specific textbook, which may influence their understanding of the topic. The discussion also reflects some uncertainty about the application of the distance formula versus component subtraction.

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Homework Statement



When you have a point in [tex]\Re[/tex]3, like for example let J(3, 7, 3) and Q(1, 2, 3). What is the distance in terms of coordinate between them? Like can you just subtract the corresponding components?

Homework Equations



I am not sure if it only works for the formula distance formula.

The Attempt at a Solution



Like what I meant was if I should try subtracting from J to Q to find (...)

J - Q = (2, 5, 0)

Does that work?

Thank you
 
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J-Q is the vector from Q to J. The distance between Q and J is the magnitude of J-Q, which is sqrt(2^2 + 5^2 + 0^2)
 
eok20 said:
J-Q is the vector from Q to J. The distance between Q and J is the magnitude of J-Q, which is sqrt(2^2 + 5^2 + 0^2)

I know how to use the distance formula, but I am wondering if I can just subtract the corresponding components. Because I am reading Mathematical Methods in Physical Science by Wiley and they subtracted the components like so
 
Yes, in order to get the displacement vector, you can just subtract components element by element. This makes sense if you think about J and Q as vectors from the origin and the displacement vector going from the head of J to the tail of Q. To find the distance, as mentioned above, you need to get the length of that vector. This procedure turns out to be equivalent to the distance formula.
 
Tedjn said:
Yes, in order to get the displacement vector, you can just subtract components element by element. This makes sense if you think about J and Q as vectors from the origin and the displacement vector going from the head of J to the tail of Q. To find the distance, as mentioned above, you need to get the length of that vector. This procedure turns out to be equivalent to the distance formula.

Thank you! I was really having qualms about this.
 

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