Coordinate Geometry: Proving Chord & Tangent of Rectangular Hyperbola

Then you would find that the equation of the tangent at point P is py+ x= 2cp. In summary, the equation of the chord PQ is pqy+x=c(p=q), and the equation of the tangent at point P is py+x=2cp.
  • #1
Harmony
203
0
The points P(cp,c/p) and Q(cq,c/q) lie on the rectangular hyperbola xy=c^2. Show that the equation of the chord PQ is pqy+x=c(p=q), and deduce the equation of the tangent at the point P.

I can do the proving. And I can find the tangent as well if the word "deduce" is not there. How can you deduce the equation by referring to the chord PQ?
 
Physics news on Phys.org
  • #2
- post deleted...I was talking out of my hat -
 
Last edited:
  • #3
Harmony said:
The points P(cp,c/p) and Q(cq,c/q) lie on the rectangular hyperbola xy=c^2. Show that the equation of the chord PQ is pqy+x=c(p=q), and deduce the equation of the tangent at the point P.

I can do the proving. And I can find the tangent as well if the word "deduce" is not there. How can you deduce the equation by referring to the chord PQ?
You mean pqy+ x= c(p-q). Remember that we can think of a tangent, at P, as being the "limit" of the chords as q goes to p. Take the limit as q goes to p of pqy+ x= c(p- q).
 
Back
Top