Coordinate Geometry: Proving Chord & Tangent of Rectangular Hyperbola

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SUMMARY

The discussion focuses on proving the equation of the chord PQ for points P(cp,c/p) and Q(cq,c/q) on the rectangular hyperbola xy=c², resulting in the equation pqy+x=c(p-q). Additionally, it explores how to deduce the equation of the tangent at point P by considering the limit of the chord as q approaches p. The key takeaway is that the tangent can be derived from the chord equation by applying the limit concept.

PREREQUISITES
  • Understanding of rectangular hyperbolas and their equations
  • Knowledge of limits in calculus
  • Familiarity with coordinate geometry concepts
  • Ability to manipulate algebraic expressions involving variables
NEXT STEPS
  • Study the properties of rectangular hyperbolas in detail
  • Learn about limits and their applications in calculus
  • Explore the derivation of tangent lines from chord equations
  • Practice problems involving coordinate geometry and hyperbolas
USEFUL FOR

Students and educators in mathematics, particularly those focusing on coordinate geometry and calculus, as well as anyone interested in the properties of hyperbolas and their tangents.

Harmony
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The points P(cp,c/p) and Q(cq,c/q) lie on the rectangular hyperbola xy=c^2. Show that the equation of the chord PQ is pqy+x=c(p=q), and deduce the equation of the tangent at the point P.

I can do the proving. And I can find the tangent as well if the word "deduce" is not there. How can you deduce the equation by referring to the chord PQ?
 
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Last edited:
Harmony said:
The points P(cp,c/p) and Q(cq,c/q) lie on the rectangular hyperbola xy=c^2. Show that the equation of the chord PQ is pqy+x=c(p=q), and deduce the equation of the tangent at the point P.

I can do the proving. And I can find the tangent as well if the word "deduce" is not there. How can you deduce the equation by referring to the chord PQ?
You mean pqy+ x= c(p-q). Remember that we can think of a tangent, at P, as being the "limit" of the chords as q goes to p. Take the limit as q goes to p of pqy+ x= c(p- q).
 

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